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In this video I will find the solution, u(x,y)=f(p)=f(x^2y)=? when u=4 when p=g(x,y)=g(1,1), to the 1st order differential equation, with 2 partial derivatives, x(partial(u)/partial(x))-2y(partial(u)/partial(y))=0; where u(x,y)=f(p)=f(x^2y).

Next video in this series can be seen at:
https://youtu.be/qt0PGdG4gY0