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In this video I will find the solution, u(x,y)=f(p)=?, to the 1st order differential equation, with 2 partial derivatives, x(partial(u)/partial(x))-2y(partial(u)/partial(y))=0; where u(x,y)=f(p)=f(x^2y) given that u(1,y)=2y+1.

Next video in this series can be seen at:
https://youtu.be/kRxk5Eu8kSs