The equation of Moment of Inertia for Circular Section is explained with following timestamps:

0:00 – Mechanics of Solid Lecture series
0:08 – Outlines on the session
0:12 – Derivation of Equation of Polar Moment of Inertia for Circular Lamina
4:47 – Derivation of Equation of Moment of Inertia for Circular Lamina

Following points are covered in this video:
1. Derivation of Equation of Polar Moment of Inertia for Circular Lamina
2. Derivation of Equation of Moment of Inertia for Circular Lamina

Engineering Funda channel is all about Engineering and Technology. Here this video is a part of Mechanics of Solids or Engineering Mechanics.

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Details of Moment of Inertia for Circular Lamina:

The moment of inertia of a circular lamina, such as a disc, about an axis passing through its center of mass and perpendicular to its plane can be calculated using the formula:

I = (1/2) * m * r^2

where I is the moment of inertia, m is the mass of the lamina, and r is the radius of the lamina.

This formula assumes that the circular lamina has a uniform mass distribution and that the axis of rotation passes through its center of mass. If the axis of rotation is displaced from the center of mass, the parallel axis theorem can be used to calculate the moment of inertia about the new axis.

The moment of inertia of a circular lamina about an axis passing through a point on its edge and perpendicular to its plane is given by:

I = (3/2) * m * r^2

where m is the mass of the lamina and r is the radius of the lamina.

These formulas are useful in physics and engineering, where the moment of inertia of circular objects is often required for designing and analyzing various mechanical systems.